Write an efficient program to find the sum of contiguous subarray within a one-dimensional array of numbers which has the largest sum.
#include<iostream>
#include<climits>
using namespace std;
int maxSubArraySum(int a[], int size)
{
int max_so_far = INT_MIN, max_ending_here = 0;
for (int i = 0; i < size; i++)
{
max_ending_here = max_ending_here + a[i];
if (max_so_far < max_ending_here)
max_so_far = max_ending_here;
if (max_ending_here < 0)
max_ending_here = 0;
}
return max_so_far;
}
int main()
{
int a[] = {-2, -3, 4, -1, -2, 1, 5, -3};
int n = sizeof(a)/sizeof(a[0]);
int max_sum = maxSubArraySum(a, n);
cout << "Maximum contiguous sum is " << max_sum;
return 0;
}
|
Output:
Maximum contiguous sum is 7
import java.io.*;
import java.util.*;
class Kadane
{
public static void main (String[] args)
{
int [] a = {-2, -3, 4, -1, -2, 1, 5, -3};
System.out.println("Maximum contiguous sum is " +
maxSubArraySum(a));
}
static int maxSubArraySum(int a[])
{
int size = a.length;
int max_so_far = Integer.MIN_VALUE, max_ending_here = 0;
for (int i = 0; i < size; i++)
{
max_ending_here = max_ending_here + a[i];
if (max_so_far < max_ending_here)
max_so_far = max_ending_here;
if (max_ending_here < 0)
max_ending_here = 0;
}
return max_so_far;
}
}
|
Output:
Maximum contiguous sum is 7
from sys import maxint
def maxSubArraySum(a,size):
max_so_far = -maxint - 1
max_ending_here = 0
for i in range(0, size):
max_ending_here = max_ending_here + a[i]
if (max_so_far < max_ending_here):
max_so_far = max_ending_here
if max_ending_here < 0:
max_ending_here = 0
return max_so_far
a = [-13, -3, -25, -20, -3, -16, -23, -12, -5, -22, -15, -4, -7]
print "Maximum contiguous sum is", maxSubArraySum(a,len(a))
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Output:
Maximum contiguous sum is 7
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